If the new operator fails to allocate memory, the exception std::bad_alloc is only getting caught if I put a try-catch block immediately surrounding the new statement. If I instead have the try-catch
this is probably something stupid, but i can\'t figure it out. I\'m getting a std::bad_alloc exception in the following code snippet (which is a case statement in a switch):
I need some clarification on an issue I don\'t quite understand. Using the two scenarios that follow, I would have thought that the amount of memory allocated would roughly be the same. However, scena
This is the offending line: Texture *texture = new Texture (...); I receive from bad_alloc here: void *__CRTDECL operator new(size_t size) _THROW1(_STD bad_alloc)
I have this code.. CEngineLayer::CEngineLayer(void) { // Incoming creation of layers. Wrapping all of this in a try/catch block is
Good afternoon ladies and gents. So, it is not my day for errors. Implementing Mergesort (not in-place) in C++, and I\'m having real trouble with the code, with no idea why. The second-to-last line of
I am writing a query processor which allocates large amounts of memory and tries to find matching documents. Whenever I find a match, I create a structure to hold two variables describing the document
I have a fairly serious bug in my program - occasional calls to new() throw a bad_alloc. From the documentation开发者_如何学Python I can find on bad_alloc, it seems to be thrown for these reasons:
I\'ve debugged my other problem back, to the MyMesh constructor. In this code: if (hollow) { numTriangles = n*8;
I have a program failing with: terminate called after throwing an instance of \'std::bad_alloc\' what():St9bad_alloc
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