Can realloc fail in this case? int *a = NULL; a = calloc(100, sizeof(*a)); printf(\"1.ptr: %d\\n\", a); a = realloc(a, 50 * sizeof(*a));
I am porting a project to the iPhone and it uses realloc and memcpy which are not found. What is the header to include?开发者_如何学编程
I have a function which is called multiple times during the program\'s execution. In said function, I have a dynamic character pointer which I resize numerous times.
This question already has answers here: What's the point of malloc(0)? (17 answers) Closed 8 years ago.
I\'m writing an app in C using win32 API. When I try to enlarge the size of my array, using the HeapRealloc() function, it changes my current values in the array, instead of copying them.
I am wondering whether the C or C++ standard guarantees that a pointer is not changed when realloc is called with a smaller (nonzero) size:
If realloc fails and 开发者_运维问答returns NULL is the former buffer free\'d or it is kept intact? I didn\'t found that particular piece of information in the man page and I\'m quite unsure what to d
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