Class clazz = ...; InputStream is开发者_如何学运维 = ClassLoader.getSystemResourceAsStream(clazz.getName().replace(\'.\', \'/\') + \".class\");
I\'m writing a spring based web application for our company and I received orders that I should encrypt classes of our app.
I want to create an OSGi framework programmatically, load a Bundle with it and load a class from that bundle. When I call Bundle.loadClass() I get a Class isntance with all fields\\methods\\constructo
I cannot easily find it in JLS/JVMSpec, nor in SO. I\'m sure it must\'ve been asked... So, what does \"new\" do actually? Suppose we instantiate a class B in A:
I have a an application (extension) running inside a Smartfox server. Most of you won\'t know Smartfox, but the setup is like Tomcat. i.e. the extension has its own classloader which loads classes fro
I开发者_高级运维s there a way to import other classes in Java without adding them to the classpath? Something like \"import C:/dir/file.jar\"?You can\'t import a jar file just by changing the \"import
Please consider the following test program (using scala 2.9.0.1) object test { def main(args:Array[String]) = {
While building project I am getting the following error: java.lang.LinkageError: JAXB 2.1 API is being loaded from the bootstrap classloader, but this RI (from jar:file:/C:/Documents and Settings/in
I have a number of classes of the same type (com.project.abc.abs.Agent) annotated like so; @Component(\"WEB.Agent-1\"), @Component(\"WEB.Agent-2\"), @Component(\"WEB.Agent-3\")... etc. For now assume
I\'ve written a custom MBean that deploys in Tomcat 6. One of its tasks is to query a database value. I\'m doing this by loading up the database resource using JNDI - the resource is defined in Tomcat
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