Assume that I have a boost::function of with an arbitrary signature called type CallbackType. Is it possible to use boost::bind to compose a function that takes the same arguments as the CallbackTy
I am trying to attach a function-object to be called on destruction of a templatized class. However, I can not seem to be able to pass the function-object as a temporary. The warning I get is (if the
Given this class: class C { private: struct Foo { int key1, key2, value; }; std::vector<Foo> fooList; };
When moving from VS2005 to VS2010 we noticed a performance decrease, which seemed to be caused by additional copies of a functor.
I have this code: #include <iostream> #include <functional> struct A { int operator()(int i) const {
I create something like a list of functors (functions pointers). Then I write them in binary form into file. The problem is, that, functor - is a simple function pointer. (correct me if I\'m wrong.) B
This questio开发者_运维问答n already has answers here: Closed 10 years ago. Possible Duplicate: In Functional Programming, what is a functor?
I recently discovered that in C++ you can overload the \"function call\" operator, in a strange way in which you have to write two pair of parenthesis to do so:
In the wikipedia article about function开发者_如何学Go objects it says such objects have performance advantages when used with for_each because the compiler can \"inline\" them.
According to the first answer to this question, the functor below should be able to retain a value after being passed to foreach ( I couldn\'t get the struct Accumulator in the example to compile, so
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