I want run to call c.drive(): #include <functional> using namespace std; struct Car { void drive() { }
I just browsed through \"C# in Depth\" and stumbled upon the following code: Func<string> stringFunc = () => \"\";
I found this code on Wikipedia class compare_class { public: bool operator()(int A, int B) const { return A < B;
How can I make (a, a) a Functor without resorting to a newtype? Basically I want it to work like this:
In an in开发者_运维问答terview they asked me if using function pointers would be beneficial (in terms of speed) when writing code for embedded systems? I had no idea on embedded system so could not an
I would like to know if it is possible to create an actual functor object from a lambda expression. I don\'t think so, but if not, why?
I would like to pass the bind1st(mem_fun(&my_class::f), this) functor to for_each. Unfortunately it is very difficult to read so I would like to give it a more readible name like this:
I have something like a sort-algorithm here, and I want to pass it a functor, which provides the sorting criteria (std::binary_function). So it should call T.operator<() for example if std::less is
Here is my map: typedef std::map<int/*security id*/, PositionMonth> PortfolioMonth; where PositionMonth is a structure, ex.:
Given the following: struct Foo { int bar() const; }; struct IsEqual : public std::unary_function<Foo*, bool>
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