I\'m creating a custom iterator type, and the only use case right now is std::for_each. But apparently, it\'s not enough to mimic the pointer interface (I\'m only doing forward iteration), there are l
Original question: I have a type template <typename CostType> struct Key which I use in another class UQueue, w开发者_C百科hich is also templated on CostType. I\'d like to not have to specify Ke
This program fails to compile(using gcc-4.5). The error message says: error: ‘myType_t’ does not name a type
The product build succeeds, but the test fails. How do I pass the type-mismatch failure reported on the line with STAssertEquals below?
I am writing an embedded application designed to run at about 3-7 MHz so speed is CRITICAL. also the device only has 32K of RAM. Dynamic memory allocation is NOT and option. That said...
Whether following structure declaration is right. typedef struct{ int roll; intage ; } class[10]; When I do like this , compiler does not say any error.
What would typedef int (&rifii) (int, int) be used for? What is the typedef before this \"statement\" do?
So my question is multifaceted. For the purpose of understanding C (not C++) I believe the following code:
This question already has an answer here: C++ template typedef (1 answer) Closed 8 years ago. How should I typedef a template class ? Something like:
Working with a piece of code right 开发者_Go百科now that features declarations of the form: typedef PACKED(struct)
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