Is it posible to use the typ开发者_开发技巧e of a prefiously declared function as a function pointer without using a typedef?
I\'m currently using boost::intrusive_ptr together with my GUI classes. Although this is more or less a convenience question, is there a proper way to get the typename of the current class?
I\'m working with legacy embedded C code which defines the types uint8_t, uint16_t and uint32_t in a header file using the typedef keyword.
typedef int (fc_name) (void); Here fc_name is 开发者_如何学Pythonany valid C symbol. How different is this from a function pointer typedef?It\'s a typedef to a function type.The intent is to use it
Edit: Foundduplicate I\'ve whittled down some problem code to the simplest working case to illustrate the following: my typedef in a pure abstract base class is not being inherited by the derived cl
If you have a boost::multi_index_container< > with multiple indices, there are obviously multiple ways to iterate over it - each index defines a way. For instance, if you have an index with tag
I faced this problem today and just wondering how to check if a new type defined with typedef is really defined somewhere. To give an example, I started using Xerces-c3 library that I built from sourc
I\'ve been working through Bjarne Stroustrup\'s \"The C++ Programming Language\" (2nd edition - I know I should really get a new copy but this is a library book!), and had a few questions about one of
Is there a built in function or a way to query the size of an emun typedef? typedef开发者_如何学运维 enum difficultyTypes {
What is the right way to typedef a type and the same type\'s pointer? Here is what I mean. Should I do this:
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