This is from a small library that I found online: 开发者_运维百科const char* GetHandStateBrief(const PostFlopState* state)
From CString to char*, ReleaseBuffer() must be used after GetBuffer(). But why? What will happen if I don\'t use ReleaseBuffer() 开发者_StackOverflow中文版after GetBuffer()?
Can anyone please tell me how to convert a C style string (i.e a char* ) to a c++ style string (i.e. std::string) in a C+开发者_如何转开发+ program?
I am writing my own string copy function. The following works: char *src, *dest; src = (char *) malloc(BUFFSIZE);
I have a C string that looks like \"Nmy stringP\", where N and P can be any character. How can I edit it into \"m开发者_StackOverflowy string\" in C?To "remove" the 1st character point to th
const char* src = \"hello\"; Calling strlen(src); returns size 5... Now say I do this: char* dest = new char[strlen(src)];
In c/c++ some people use c-styled strings l开发者_运维问答ike: char *str = \"This is a c-styled string\";
加载中,请稍侯......