What\'s the best way to disguise a Python program using urllib2?I know how to set the user-agent which is a good start.But what about other items like the referring URL?Any way to set that?Any other s
cj = cookielib.CookieJar() opener = urllib2.build_opener(urllib2.HTTPCookieProcessor(开发者_如何学运维cj))
I\'m trying to read the source of a website with this code: import urllib2 z=urllib2.urlopen(\'http://skreemr.com/results.jsp?q=said+the+whale&search=SkreemR+Search\')
I have this code: import urllib2 import thread a = 0 def workers(): while 1: a+=1 silva = urllib2.urlopen(\'http://en.dilandau.eu/download_music/said-the-whale-\'+str(a)+\'.html\')
i have to retrieve some text from a website called morningstar.com . To access that data i have to log in. Once i log in and provide the urlof the web page,i get the HTML text of a normal user (not lo
I want to catch a urllib2.HTTPError with extra information if it\'s a 404: try: data = urlopen(url) except HTTPError, e:# Python 2.5 syntax
I have a perl program that retrieves data from the dat开发者_运维知识库abase of my university library and it works well. Now I want to rewrite it in python but encounter the problem
I want to integrate a credit card processing in my website using Paybox.com API\'s. I have to send a POST request (usin开发者_StackOverflowg urllib2) to Paybox API\'s with credit card details (number
I am trying to write my first Python script, and with lots of Googling, I think that I am just about done. However, I will need some help getting myself across the finish line.
I\'m using the Harvest API (http://www.getharvest.com/api).When a client goes over it\'s quota, a 503 response is returned.In that response there should be a header called \"Retry-After\" that tells m
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