Is there a direct way of getting the Nth combination of an ordered set of all combinations of nCr? Example: I have four elements: [6, 4, 2, 1]. All the possible combinations by taking three at a time
I\'ve been trying to find an answer to this for months (to be used in a machine learning application), it doesn\'t seem like it should be a terribly hard problem, but I\'m a software engineer, and mat
Closed. This question does not meet Stack Overflow guidelines. It is not currently accepting answers.
I\'m working on a web application which will be used for classifying photos of automobiles. The users will be presented with photos of various vehicles, and will be asked to answer a series of questio
I saw this code in a comment for the article \"Never-ending Shuffled Sequence\". I开发者_如何学运维 understand the basic premise, but I don\'t know how it works. The biggest explanation I need is of t
加载中,请稍侯......