I understand that in C++ double underscores in identifiers are reserved for the compiler. I have some C code which has character开发者_如何转开发istics similar to this in the corresponding header file
I have an app named MyApp which is linked to a static library MyLibrary I\'ve ad开发者_JS百科ded the MyLibrary project to Xcode and added the MyLibrary target to MyApp\'s target dependencies.
I know that #define replaced before the compiling to real values. so why the first code here compile with no error, and the 2nd not?
Consider this code: #define N_ 0 #define N_X 1 #define M(a) N_ M(arg)X;//#1 -- I\'d like this to expand to N_X, and ultimately 1; but it\'s 0X instead
I\'d like to pass the name of an include file as a compiler argument so that I can modify a large number of configuration parameters.However, my C++ build is via a makefile like process that removes q
I have a Unicode Win32 application that uses 3rd party libraries, some of which provide constants for their version information as #defined (narrow) strings.For instance, libpng has the following:
How does the following piece of code work, in other words what is the algori开发者_运维问答thm of the C preprocessor? Does this work on all compilers?
The C99 standard document has the following example in the section related to the ## preprocessing operator:
We have several projects in development sharing the same codebase. Certain pieces of code are only relevant to one or other of those projects.
This question already has answers here:开发者_C百科 Closed 11 years ago. Possible Duplicate: How to convert concatenated strings to wide-char with the C preprocessor?
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