C doesn\'t have (to the best of my knowledge) overloading or templates, right? So how can a set of type-agnostic functions with the same name exist in plain ol\' C? The usual compile-time trickery wou
If I have a parent-child that defines some method .foo() like this: class Parent { public void foo(Parent arg) {
Today, looking at the man page for open(), I\'ve noticed this function is \'overloaded\': int open(const char *pathname, int flags);
I have two overloaded methods, one with an optional parameter. void foo(string a){ } void foo(string a, int b = 0) { }
This question already has answers here: Closed 12 years ago. Possible Duplicates: C++ method only visible when object cast to base class?!
The following code does not compile: #include <iostream> class Foo { std::string s; public: const std::string& GetString() const { return s; }
I\'ve been reading 开发者_如何学Pythonabout overloading true and false in C#, and I think I understand the basic difference between this and defining a bool operator.The example I see around is someth
I want to use magic function __set() and __get() for storing SQL data inside a php5 class and I get some strange issue using them inside a function:
Given I have a class wi开发者_Python百科th two constructors: public class TestClass { ObjectOne o1;
Still wrapping my开发者_如何转开发 head around Delegates and I\'m curious: Is it possible to overload anonymous functions?
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