What is the d开发者_StackOverflowifference between overloading the operator = in a class and the copy constructor?
consider the following: class X { public: X(int i) { cout << \"X(int i)\" << endl; } X(const X& x) { cout << \"X(const X& x)\" << endl; }
I\'m using a Class (Object) that doesn\'t have any copy operator : it basically cannot be copied right now. I have a
While there is quite a few questions about copy constructors/assignment operators on SO already, I did not find an answer that fit my problem.
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I\'m not very good at this, and I am a bit stuck making the copy constructor for a single linked list and the nodes 开发者_StackOverflow社区that go with it.
Sometimes it\'s necessary to prohibit a copy constructor in a C++ class so that class becomes \"non-copyable\". Of course, operator= should be prohibited at the same time.
The idea of copy constructor really confuses me.I don\'t understand 开发者_开发技巧why they use references and why constant references in copy constructor?Why you use a reference: if you didn\'t, you\
Suppose the class MyClass has constructor: MyClass::MyClass( ... ) { var = new OtherClass( ... ); } and suppose the class OtherClass has copy constructor:
As we know, if any constructor is declared (copy constructor included), default constructor (the one that takes no arguments) is not implicitly created. Does the same hap开发者_如何学编程pen with a de
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