Is is possible to use std::map in C++ with a class without any copy operator?

I'm using a Class (Object) that doesn't have any copy operator : it basically cannot be copied right now. I have a

std::map<int,Object> objects

variable that lists objects with an int identifier. How could I add an Object to this map without having to use copy operators? I tried

objects.insert(std::pair<0,Object()>);

but that won't compile. I would just like to create my object initially inside the map using the de开发者_StackOverflowfault constructor, but writing

objects[0]; fails... Thanks :)

In C++03, objects that are stored in STL containers must be copyable. This is because a STL container's std::allocator actually uses the placement version of the new operator to copy construct the objects in pre-allocated memory blocks, and that requires the existence of a copy-constructor to copy the actual instance of the object you're wanting to add to the container into the memory address that had been pre-allocated by the container's allocator. So your only option would be to store pointers to your objects rather than the objects themselves. Therefore, you could do the following:

std::map<int, std::shared_ptr<Object> > objects;
objects.insert(std::pair<int, std::shared_ptr<Object> >(0, new Object());

Not in C++03. How are you going to get the object from wherever it is now into the map without a copy constructor?

In C++0x then you could move into the map, and in theory, perfectly forward to construct one in place from other arguments.

Edit: You could swap it, if it's swappable, and you can default construct it in-place using operator[].

std::map<int, Object> objmap;
objmap[2]; // Default-constructs an Object in-place
std::swap(objmap[2], Object()); // Swaps it into the map.

Since your object is not copy-constructible, you could create your map containing shared_ptr :

std::map<int,shared_ptr< Object > >

That takes care of destruction of objects.