I\'m testing Zen_DB and Zend_DB_Table and I\'m facing a problem: Let\'s say I\'ve got two tables table A(id, title)
I am trying to build the following SQL statement: SELECT `users_table`.*, `users_data`.`first_name`, `users_data`.`last_name`
I want to join two tables in differenet databases on the same server. Could someone tell me how I could d开发者_运维问答o this in Zend Frameworks Db adapter?see:
I apologize if my title is a bit misleading and it turns out that it\'s some other class under Zend_Db.
I am using Zend Framework. I want the current user (if logged in) to always be available to the view.In my Bootstrap.php file I currently have:
I have a problem with inserting a letter that is not an A-Z char. For example: $fullTag = \'świat\'; A \'letter\' should contains ś
This is the second time that I\'ve noticed this... I am running my Zend Framework a开发者_开发技巧pplication on my laptop, but connecting to my remote database. It works fine most of the time (from h
I keep getting this error in my application and can\'t figure out what it means and where it\'s happening. I know it\'s in one of my models but I don\'t understand the error.
I am implementing my model exactly like the quickstart guide. In my model I am trying to implement a findByToken() method. The current find() method accepts an $id parameter, but I want to find by th
I have the following code: public function checkLoginDetails($email, $password) { $select = $this->select ();
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