Zend Framework: How to find a table row by the value of a specified column?
I am implementing my model exactly like the quickstart guide.
In my model I am trying to implement a findByToken()
method. The current find()
method accepts an $id
parameter, but I want to find by the value of a different column.
//excerpt from the quickstart guide
public function find($id, Default_Model_Guestbook $guestbook)
{
$result = $this->getDbTable()->find($id);
if (0 == count($result)) {
return;
}
$row = $result->cu开发者_开发百科rrent();
$guestbook->setId($row->id)
->setEmail($row->email)
->setComment($row->comment)
->setCreated($row->created);
}
I tried doing something like this, but I don't think it worked:
$db = $this->getDbTable();
$where = $db->getAdapter()->quoteInto('token = ?', $token);
$result = $db->find($where);
What would be the proper way to find a row by the value of a specified column?
$result = $db->fetchAll($where);
or if you are trying to retrieve only one row.
$result = $db->fetchRow($where);
You could also use the Zend_Db_Select Object, keeping the adapter a little further abstracted:
$db = $this->getDbTable();
$select = $db->select()->where('token = ?', $token);
$result = $db->fetchAll($select);
This can be easily done by creating select object and fetching a row using this object. It's well described in manual: http://framework.zend.com/manual/en/zend.db.select.html#zend.db.select.execute
Your code could look like:
$select = $this->getDbTable()->select()->where('token = ?', (string) $token);
$row = $this->getDbTable()->fetchRow($select);
精彩评论