If I divi开发者_如何转开发de by 0, I get either a ZeroDivisionError, Infinity or NaN depending on what is divided.
How come that in the following snippet int a = 7; int b = 3; double c = 0; c = a / b; c ends up having the value 2, rather than 2.3333, as one would expect. If a and b are doubles, the answer does
You could write something like: int i = 3; int k = 2; int division = i / k; int remainder = i % k; It seems as thought this would, on a low level, ask an ALU to perform two vision operations: one r
I need to do an integer division in a kernel module and I am using do_div() for that. It seems to work on my machine (I have an i686 processor), however I am not sure that it works everywhere. Could a
In VB.NET even if both the operands are integer, the / operator will cause the value to be floating point (if the result is non开发者_开发百科 integer).
I\'m working with Visual C++ 2008 here (9.x) and I was preparing a fixed point value when I ran into the compiler generating a DIV instead of an IDIV. I collapsed the code into a tiny piece to exactly
Just curious about something. While converting HTML colors (whose individual color components are represented via 2-digit hexadecimal values) to floats开发者_开发问答 between 0.0 and 1.0 so we can use
Why does this calcuation: d开发者_如何转开发ouble number = (13 /(13+12+13)) equals 0? It should be around 0.34, I think!
Which is the best way, in C, to see if a number is divisible by another? I use this: if (!(a % x)) { // this will be executed if a is divisible by x
Is there a g++ warning or other tool that can identify integer division (truncation toward zero)?I have thousands of lines of code with calculations that inevitably will have numerical errors typicall
加载中,请稍侯......