I\'m trying to use a regular expression to erase only the matching part of an string.I\'m using the preg_replace function and have 开发者_如何学Pythontried to delete the matching text by putting paren
I\'m having a regular expression (\\\\w+[ ]*|-\\\\w+[ ]*)(!=|<=|>=|=|<|>| not in | in | not like | lik开发者_如何学JAVAe )(.*)
I have this regex to identify if the line contains two underscores: \\s*_{2}(\\w+) Any space, two underscores and then a word.It turns out, I need to know also for no underscore at all, so I have:
I have this sample string: Image:SGD$45.32 SKU: 3f3f3 dfdfd grg4t BP 6yhf Pack Size: 1000\'s Color: Green Price: SGD$45.32 SGD$45...
I\'m looking for a RegEx that will find Select Case Statements that have no Case Else in them. Here\'s what I came up with so far
How to preg_replace() with a single line to achieve the following outputs? $string1=\"get rid1 [link1] get rid2 [link2] ...\"; // any number of开发者_StackOverflow社区 links
I am not开发者_如何学运维 sure if this is possible to do, but I need a way to replace a value of a numbered group specified in the my regex expression with a string declared dynamically at runtime, on
How are non-capturing groups, i.e., (?:), used 开发者_如何学运维in regular expressions and what are they good for?Let me try to explain this with an example.
I want to match text inside double quotes and bracket as two groups by use regex, How can I do that? from
Can anyone explain: Why the two patterns used below give different results? (answered below) Why the 2nd example gives a group count of 1 but says the start
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