I have a table that stores date/time v开发者_运维问答alues as julian days in SQLite (using the julianday() function). I can\'t seem to figure out how to convert them back to ISO 8601 style strings (YY
I have a year (2002) and I\'m trying to get it into the following format: 2002-00-00T00:00:00 I tried various iterations, the last of which was this:
Wikipedia gives an exa开发者_开发技巧mple of an ISO 8601 example of a repeating interval: R5/2008-03-01T13:00:00Z/P1Y2M10DT2H30M
In a Bash script, I want to print the current datetime in ISO 8601 format (preferably UTC), and it seems that this should be as simple as date -I:
In VBScript, does FormatDateTime have ISO 8601 support? If not, how would I write such function with i开发者_如何转开发t?
I can convert a Delphi TDate to ISO 8601 format easily using this: DateTimeToString(result, \'yyyy-mm-dd\', myDate);
All of the events for Full Calendar are showing as \"all day\" in the agenda views.This is the code that I am using to initialize the calendar :
According to ISO 8601, time can be specified in different formats. My program does not know which exact ISO 8601 format wil开发者_高级运维l be specified.
I h开发者_JS百科ave a SQLite database where I store the dates as ticks. I am not using the default ISO8601 format. Let\'s say I have a table defined as follows:
I\'m kind of stunned that the python datetime .isoformat() function doesn\'t return correct information.The function correctly returns an ISO 8601-formatted string when a timezone is provided to the f
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