Is there a way to bring back a date formatted with SimpleDateFormat to its long equivalent (like开发者_高级运维 System.currentTimeMillis())?DateFormat format = new SimpleDateFormat(\"yyyy-MM-dd\");
I\'d like to know how to make a simple program where user can gave 2 input time(hh:mm) forma开发者_开发技巧t ---and receive the elapsing time as the output.
I am trying to parse datetime string with SimpleDateFormat.parse() but I keep receiving Unparseable date exceptions.
I have searched throughout the site but I think I have a slightly different issue and could really do with some help before I either have heart failure or burn the computer.
I have a problem parsing just the time string from my database private static final String TIME_FORMAT = \"HH:mm:ss\";
I\'ve got date in following format: Pon Cze 07, 2011 9:42 pm It\'s Polish equivalent of English date: Mon Jun 07, 2011 9:42 pm
I\'m new in Andy world. I\'m doing mine first app. GPS tracker. I need to save coordinates + (time ,date) to file on SD.
The following test fails: DateFormat df = new SimpleDateFormat(\"HH:mm:ss z\"); assertEquals(\"00:00:00 GMT\", df.format(new Date(0)));
SimpleDate开发者_运维问答Format formatter = new SimpleDateFormat(\"yyyy-MM-dd\"); Date date = (Date)formatter.parse(\"2011-09-13\");
I am working on an XML Parser for Android with twelve different items and I need help creating a date for e开发者_运维技巧ach item. This is what I have so far:
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