I have a class that looks roughly like this: template<std::size_t dim> class Foo { public: Foo(void const * const data);
Let\'s try this 开发者_StackOverflow: float test = 3.56; float roundedVal = round(test * 10.0f) / 10.0f;
I have a piece of code that needs to repetitively calculate the following... double consumption = minConsumption + ( Math.random() * ( ( maxConsumption - minConsumption ) + 1 ) );
I have a form in which users can enter prices for items. Ideally I want the user to be able to add prices in whatever method feels best to them and also for readability. I then need to convert this to
I have a C function that returns a type float. When the function returns 1.0f, the receiver sees 1065353216, not 1.0.
I\'m using GCC to compile a program which adds floats, longs, ints and ch开发者_运维技巧ars. When it runs, the result is bad. The following program unexpectedly prints the value of 34032.101562.
I can\'t achieve r开发者_JAVA技巧ounding a float. Those calls all returns me 3.5999999 and not 3.6 for theoTimeoutTrick and theoTimeout.
I have the following two possible contents of a String. Obviously the amounts always vary and I would like to extract the key information and
I am writing a program for an embedded hardware that only supports 32-bit single-precision floating-point arithmetic. The algorithm I am implementing, however, requires a 64-bit double-precision addit
I have a little technical question, is it the same to call: public static strictfp double myMethod(double phi){
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