I have a value thats 5 bits in length. 4 bits determine the number and the 5th bit determines the sign, there by holding any value between -16 and +15. How can I accomplish sign extending from a const
Following up my previous bit-twiddling question, now I\'m looking to trim down the method that uses that one (though, an unbuffered version, since the life of the array is only this object).This is th
Given this code which prints all the bits in an integer out: private string getBitLiteral(bool bitVal)
I am decomposing a single long into a long[] of single bit longs by public static int decompose(long[] buffer, long base) {
There is a variable that holds some flags and I want to remove one of them. But I don\'t know how to remove it.
Check whether a number x is nonzero using the legal operators except !. Examples: isNonZero(3) = 1, isNonZero(0) = 0
This is probably a dumb question came to my mind, but I think I don\'t have answer to this - How processor would find if A < B? In fact there are other things as well like A>B or A==B.
int x = 2; x = rotateInt(\'L\', x, 1); // should return 4 x = rotateInt(\'R\', x, 3); // should return 64
I\'m trying to understand how bit开发者_如何学运维 shift works. Can someone please explain the meaning of this line:
This question already has answers here: 开发者_开发百科Closed 12 years ago. Possible Duplicate: Absolute Beginner's Guide to Bit Shifting?
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