Hello I have a binary string length of n.My goal is that all bit in string will be equal to \"1\". I can flip every bit of the string that I want but after fliping the bits of the string it does rando
First, this can be a general algorithm for any language, but I\'m learning C and if there is some C specific features, I\'d like to know!
byte s[] = getByteArray() for(.....) Integer.toHexString((0x000000ff & s[i]) | 0xffffff00).subst开发者_Python百科ring(6);
I am looking for a clean way to list the (8 bit) integers whose binary representation is not the same as another integer up to rotation and reflection.
Is there a bit operation or a series of bit operation开发者_开发百科s that would give me the following result?
Using winAVR for the following code. I got an 8-bit PIN here that I need to OR it with 00000010 or 0x02 to set the 7th bit.
In C#, is it possible to perform a sum of two 32-bit integers without using thi开发者_如何学运维ngs like if..else, loops etc?
I got stuck with the following Python code >>> a = 0xff >>开发者_JAVA百科> b = 1 << 8
#define SwapByte4(ldat开发者_Go百科a) \\ (((ldata & 0x000000FF) << 24) | \\ ((ldata & 0x0000FF00) << 8) | \\
I am trying to figure out how exactly arithmetic bit-shift operators work in C, and how it will affect signed 32-bit integers.
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