I am trying to create a function in VC++ that takes a function pointer but I keep getting syntax errors.
I\'m building a series of predicates that duplicate lots of code, and so are being changed into a single template function class based on the std::unary_function. The idea is that my class interface r
This question alre开发者_C百科ady has answers here: Closed 12 years ago. Possible Duplicate: What is the point of function pointers?
In particular, will the following ever not work as expected: typedef void(*func_p)(void*); void foo(int* data)
can I do something like: typedef void (*functor)(void* param); //machine code of function char functionBody[] = {
I read somewhere that a lambda function should decay to function pointer if the capture list is empty. The only reference I can find now 开发者_StackOverflow中文版is n3052. With g++ (4.5 & 4.6) it
Is there a way in C++ to effectively create a closure which will be a function poi开发者_如何学Cnter? I am using the Gnu Scientific Library and I have to create a gsl_function. This function needs to
I want to write code like this: /*something*/ Fn() { ... } int main() { /*something*/ fn = Fn; while(fn) fn = fn();
Is something like this possible in C? #include <stdio.h> void print_str(char *str) { printf(str);
I\'m having trouble with inserting some value_pairs into a map. Here\'s the basic idea. // private typedef Foo* (*Bar)( const std::string &x, int y );
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