Is there an开发者_StackOverflow中文版y concise way to convert a Seq into ArrayBuffer in Scala?scala> val seq = 1::2::3::Nil
After having a look at these two threads: Does F# have an equivalent to Haskell's take? , Take N elements from sequence with N different indexes in F#
Trying the following in 2.8.1/2.9.0.1 REPL, the first gives an error. val l = List(Vector(1,2), List(3,4,5))
all! What is wrong with this code? I cannot understand what I am doing wrong with Seq.Map. Here is the error message: The type \'unit\' is not compatible with the type \'seq<\'a>\'
What\'s the differ开发者_开发百科ence? Does seq guarantee more flow conditions?They aren\'t related at all.
I should split seq<a> into seq<seq<a>> by an attribute of the elements. If this attribute equals by a given value it must be \'splitted\' at that point. How can I do that in FSharp?
I have a seq of seqs in FSharp. I want to join a seq to the previous one if a predicate returns to true for it.
I wan开发者_JAVA技巧t to feed the members of a lazy seq produced by map as individual arguments to another function. Is there a function that splices a (lazy) seq? Use apply.
I need a sequence of repeated numbers, i.e. 1 1 ... 1 2 2 ... 2 3 3 ... 3 etc. The way I implemented this was:
Ok, So I need a list of all the positive integers. What first comes to mind is: let numbers:Seq<bigint>=Seq.initInfinite n...
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