I would like to construct a dataframe row-by-row in R. I\'ve done some searching, and all I came up with is the suggest开发者_StackOverflow社区ion to create an empty list, keep a list index scalar, th
I have a data frame with several columns. rows have names. I want to calcu开发者_如何学Pythonlate some value for each row (col1/col2) and create a new data frame with the original row names. If I jus
I have the following data frame: Date1Date2Date3Date4Date5 125 April 2开发者_StackOverflow社区00510 May 200628 March 200714 November 20071 April 2008
The following R code generates a snippet from data frame I am working with at the moment: rep1 <- c(\"20/02/01\",\"23/03/02\")
I\'d 开发者_高级运维like to convert my csv files into xts objects as efficiently as possible. I seem to be stuck though with having to first applying the read.zoo method to create a zoo objects before
I have an R data frame: > tab1 patt conc 1P10788 2P15720 3P1 10655 4P20644 5P25589 6P2 10544 I am trying to create a new column for conc as a percentage of conc at t=0 for each patient. As well
I have a data.frame which I would like to convert to a list by rows, meaning each row would correspond to开发者_运维知识库 its own list elements. In other words, I would like a list that is as long as
I have an XTS timeseries in R of the following format and am trying to do some processing, subsetting and re-arranging before exporting as a CSV for work in another program.
Is there a reason why R won\'t allow me to have a number as the column name of my dataframe? Also noticed that if i do data.frame(XX) it adds an X to all the column开发者_开发技巧 headers that have
I want to create a function that takes a dataset name and a package name and returns the dataset as data.frame. Here is my try
加载中,请稍侯......