web.py + subprocess = hang
Here's my main file:
import subprocess, time
pipe = subprocess.PIPE
popen = subprocess.Popen开发者_如何学JAVA('pythonw -uB test_web_app.py', stdout=pipe)
time.sleep(3)
And here's test_web_app.py:
import web
class Handler:
def GET(self): pass
app = web.application(['/', 'Handler'], globals())
app.run()
When I run the main file, the program executes, but a zombie process is left hanging and I have to kill it manually. Why is this? How can I get the Popen to die when the program ends? The Popen only hangs if I pipe stdout and sleep for a bit before the program ends.
Edit -- here's the final, working version of the main file:
import subprocess, time, atexit
pipe = subprocess.PIPE
popen = subprocess.Popen('pythonw -uB test_web_app.py', stdout=pipe)
def kill_app():
popen.kill()
popen.wait()
atexit.register(kill_app)
time.sleep(3)
You have not waited for the process. Once it's done, you have to call popen.wait
.
You can check if the process is terminated using the poll
method of the popen
object to see if it has completed.
If you don't need the stdout of the web server process, you can simply ignore the stdout option.
You can use the atexit module to implement a hook that gets called when your main file exits. This should use the kill
method of the Popen
object and then wait
on it to make sure that it's terminated.
If your main script doesn't need to be doing anything else while the subprocess executes I'd do:
import subprocess, time
pipe = subprocess.PIPE
popen = subprocess.Popen('pythonw -uB test_web_app.py', stdout=pipe, stderr=pipe)
out, err = popen.communicate()
(I think if you specifically pipe stdout back to your program, you need to read it at some point to avoid creating zombie processes - communicate will read it in a reasonably safe way).
Or if you don't care about parsing stdout / stderr, don't bother piping them:
popen = subprocess.Popen('pythonw -uB test_web_app.py')
popen.communicate()
精彩评论