is it possible to convert bitset<8> to an array of characters of integers?
I have bitset<8> v8
and its value is something li开发者_运维百科ke "11001101", something in binary, how can we convert it to an array of characters or integers in c++?
To convert to an array of char, you could use the bitset::to_string()
function to obtain the string representation and then copy individual characters from that string:
#include <iostream>
#include <algorithm>
#include <string>
#include <bitset>
int main()
{
std::bitset<8> v8 = 0xcd;
std::string v8_str = v8.to_string();
std::cout << "string form: " << v8_str << '\n';
char a[9] = {0};
std::copy(v8_str.begin(), v8_str.end(), a);
// or even strcpy(a, v8_str.c_str());
std::cout << "array form: " << a << '\n';
}
vector<int> ints;
for(int i = 0 ; i < v8.size() ; i++ )
{
ints.push_back(v8[i]);
}
Likewise, you can make an array of chars. Or you may use raw array as:
char chars[8];
for(int i = 0 ; i < v8.size() ; i++ )
{
chars[i] = v8[i];
}
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