parse query string with urllib in Python 2.4
Using Python2.4.5 (don't ask!) I want to parse a query string and get a dict in return. Do I have to do it "manually" like follows?
>>> qs = 'first=1&second=4&third=3'
>>> d = dict([x.split("=") for x in qs.sp开发者_如何学编程lit("&")])
>>> d
{'second': '4', 'third': '3', 'first': '1'}
Didn't find any useful method in urlparse
.
You have two options:
>>> cgi.parse_qs(qs)
{'second': ['4'], 'third': ['3'], 'first': ['1']}
or
>>> cgi.parse_qsl(qs)
[('first', '1'), ('second', '4'), ('third', '3')]
The values in the dict returned by cgi.parse_qs()
are lists rather than strings, in order to handle the case when the same parameter is specified several times:
>>> qs = 'tags=python&tags=programming'
>>> cgi.parse_qs(qs)
{'tags': ['python', 'programming']}
this solves the annoyance:
d = dict(urlparse.parse_qsl( qs ) )
personally i would expect there two be a built in wrapper in urlparse. in most cases i wouldn't mind to discards the redundant parameter if such exist
import urlparse
qs = 'first=1&second=4&third=3&first=0'
print dict(urlparse.parse_qsl(qs))
OR
print urlparse.parse_qs(qs)
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