How to get a random value from dictionary?

How can I get a random pair from a dict? I'm making a game where you need to guess a capital of a country and I need questions to appear randomly.

The dict looks like {'VENEZUELA':'CARACAS'}

开发者_开发百科How can I do this?

One way would be:

import random
d = {'VENEZUELA':'CARACAS', 'CANADA':'OTTAWA'}
random.choice(list(d.values()))

EDIT: The question was changed a couple years after the original post, and now asks for a pair, rather than a single item. The final line should now be:

country, capital = random.choice(list(d.items()))

I wrote this trying to solve the same problem:

https://github.com/robtandy/randomdict

It has O(1) random access to keys, values, and items.

If you don't want to use the random module, you can also try popitem():

>> d = {'a': 1, 'b': 5, 'c': 7}
>>> d.popitem()
('a', 1)
>>> d
{'c': 7, 'b': 5}
>>> d.popitem()
('c', 7)

Since the dict doesn't preserve order, by using popitem you get items in an arbitrary (but not strictly random) order from it.

Also keep in mind that popitem removes the key-value pair from dictionary, as stated in the docs.

popitem() is useful to destructively iterate over a dictionary

>>> import random
>>> d = dict(Venezuela = 1, Spain = 2, USA = 3, Italy = 4)
>>> random.choice(d.keys())
'Venezuela'
>>> random.choice(d.keys())
'USA'

By calling random.choice on the keys of the dictionary (the countries).

Try this:

import random
a = dict(....) # a is some dictionary
random_key = random.sample(a, 1)[0]

This definitely works.

This works in Python 2 and Python 3:

A random key:

random.choice(list(d.keys()))

A random value

random.choice(list(d.values()))

A random key and value

random.choice(list(d.items()))

Since the original post wanted the pair:

import random
d = {'VENEZUELA':'CARACAS', 'CANADA':'TORONTO'}
country, capital = random.choice(list(d.items()))

(python 3 style)

If you don't want to use random.choice() you can try this way:

>>> list(myDictionary)[i]
'VENEZUELA'
>>> myDictionary = {'VENEZUELA':'CARACAS', 'IRAN' : 'TEHRAN'}
>>> import random
>>> i = random.randint(0, len(myDictionary) - 1)
>>> myDictionary[list(myDictionary)[i]]
'TEHRAN'
>>> list(myDictionary)[i]
'IRAN'

When they ask for a random pair here they mean a key and value.

For such a dict where the key:values are country:city,

use random.choice().

Pass the dictionary keys to this function as follows:

import random
keys = list(my_dict)
country = random.choice(keys)

You may wish to track the keys that were already called in a round and when getting a fresh country, loop until the random selection is not in the list of those already "drawn"... as long as the drawn list is shorter than the keys list.

Since this is homework:

Check out random.sample() which will select and return a random element from an list. You can get a list of dictionary keys with dict.keys() and a list of dictionary values with dict.values().

I am assuming that you are making a quiz kind of application. For this kind of application I have written a function which is as follows:

def shuffle(q):
"""
The input of the function will 
be the dictionary of the question
and answers. The output will
be a random question with answer
"""
selected_keys = []
i = 0
while i < len(q):
    current_selection = random.choice(q.keys())
    if current_selection not in selected_keys:
        selected_keys.append(current_selection)
        i = i+1
        print(current_selection+'? '+str(q[current_selection]))

If I will give the input of questions = {'VENEZUELA':'CARACAS', 'CANADA':'TORONTO'} and call the function shuffle(questions) Then the output will be as follows:

VENEZUELA? CARACAS
CANADA? TORONTO

You can extend this further more by shuffling the options also

With modern versions of Python(since 3), the objects returned by methods dict.keys(), dict.values() and dict.items() are view objects*. And hey can be iterated, so using directly random.choice is not possible as now they are not a list or set.

One option is to use list comprehension to do the job with random.choice:

import random

colors = {
    'purple': '#7A4198',
    'turquoise':'#9ACBC9',
    'orange': '#EF5C35',
    'blue': '#19457D',
    'green': '#5AF9B5',
    'red': ' #E04160',
    'yellow': '#F9F985'
}

color=random.choice([hex_color for color_value in colors.values()]

print(f'The new color is: {color}')

References:

• *Python 3.8: Standard Library Documentation - Built-in types: Dictionary view objects
• Python 3.8: Data Structures - List Comprehensions:

I just stumbled across a similar problem and designed the following solution (relevant function is pick_random_item_from_dict; other functions are just for completeness).

import random


def pick_random_key_from_dict(d: dict):
    """Grab a random key from a dictionary."""
    keys = list(d.keys())
    random_key = random.choice(keys)
    return random_key


def pick_random_item_from_dict(d: dict):
    """Grab a random item from a dictionary."""
    random_key = pick_random_key_from_dict(d)
    random_item = random_key, d[random_key]
    return random_item


def pick_random_value_from_dict(d: dict):
    """Grab a random value from a dictionary."""
    _, random_value = pick_random_item_from_dict(d)
    return random_value

# Usage
d = {...}
random_item = pick_random_item_from_dict(d)

The main difference from previous answers is in the way we handle the dictionary copy with list(d.items()). We can partially circumvent that by only making a copy of d.keys() and using the random key to pick its associated value and create our random item.

Try this (using random.choice from items)

import random

a={ "str" : "sda" , "number" : 123, 55 : "num"}
random.choice(list(a.items()))
#  ('str', 'sda')
random.choice(list(a.items()))[1] # getting a value
#  'num'

To select 50 random key values from a dictionary set dict_data:

sample = random.sample(set(dict_data.keys()), 50)

I needed to iterate through ranges of keys in a dict without sorting it each time and found the Sorted Containers library. I discovered that this library enables random access to dictionary items by index which solves this problem intuitively and without iterating through the entire dict each time:

>>> import sortedcontainers
>>> import random
>>> d = sortedcontainers.SortedDict({1: 'a', 2: 'b', 3: 'c'})
>>> random.choice(d.items())
(1, 'a')
>>> random.sample(d.keys(), k=2)
[1, 3]

I found this post by looking for a rather comparable solution. For picking multiple elements out of a dict, this can be used:

idx_picks = np.random.choice(len(d), num_of_picks, replace=False) #(Don't pick the same element twice)
result = dict ()
c_keys = [d.keys()] #not so efficient - unfortunately .keys() returns a non-indexable object because dicts are unordered
for i in idx_picks:
    result[c_keys[i]] = d[i]

Here is a little Python code for a dictionary class that can return random keys in O(1) time. (I included MyPy types in this code for readability):

from typing import TypeVar, Generic, Dict, List
import random

K = TypeVar('K')
V = TypeVar('V')
class IndexableDict(Generic[K, V]):
    def __init__(self) -> None:
        self.keys: List[K] = []
        self.vals: List[V] = []
        self.dict: Dict[K, int] = {}

    def __getitem__(self, key: K) -> V:
        return self.vals[self.dict[key]]

    def __setitem__(self, key: K, val: V) -> None:
        if key in self.dict:
            index = self.dict[key]
            self.vals[index] = val
        else:
            self.dict[key] = len(self.keys)
            self.keys.append(key)
            self.vals.append(val)

    def __contains__(self, key: K) -> bool:
        return key in self.dict

    def __len__(self) -> int:
        return len(self.keys)

    def random_key(self) -> K:
        return self.keys[random.randrange(len(self.keys))]

b = { 'video':0, 'music':23,"picture":12 } 
random.choice(tuple(b.items())) ('music', 23) 
random.choice(tuple(b.items())) ('music', 23) 
random.choice(tuple(b.items())) ('picture', 12) 
random.choice(tuple(b.items())) ('video', 0)