this is the input and i want to print the output as follows: which command or how can we do that?

this is the input

 iws 3211296 3178534   0   Jan 19      -  0:00 iws_trs 000 0 1 2
 iws 3539162 3526750   0   Jan 19      -  0:00 iws_trs 000 0 1 2 4
 iws 3584214 3535080   0   Jan 19      -  0:00 iws_trs 000 0 1 2 3
 iws 3928194 3952828   0   Jan 19      -  0:00 iws_trs 000 0 1 1 4
 iws 3928195 3952828   0   Jan 开发者_运维知识库19      -  0:00 iws_trs 000 0 1 3 5

output: which contains 4 at the end

 iws 3539162 3526750   0   Jan 19      -  0:00 iws_trs 000 0 1 2 4

 iws 3928194 3952828   0   Jan 19      -  0:00 iws_trs 000 0 1 1 4

Which UNIX command can I use or how can we do that?

You can grep for 4$ (the $ means end-of-line).

$ grep '4$'  foo.txt
 iws 3539162 3526750   0   Jan 19      -  0:00 iws_trs 000 0 1 2 4
 iws 3928194 3952828   0   Jan 19      -  0:00 iws_trs 000 0 1 1 4

Assuming that the input is coming in from a file, you can use fgrep for this.

Read more here http://nixdoc.net/man-pages/FreeBSD/man1/fgrep.1.html