Whats the problem with this preg_match script?

Why does this code not give me any results?

if(preg_match('#referer\.php\?url=(.*?)#s',$result,$array2)) { 
    echo $array2[1]; 
}

The thing开发者_JS百科 is, if I change echo $array2[1] to echo "test"; it will show me test. So the problem doesnt seem to be the preg_match algorithm, does it? What could be the problem?

I want to have the url, which is written after the url=, for example referer.php?url=http://www.example.com should give http://www.example.com as result in the $array2.

Thanks for your help!

try changing it this way:

if(preg_match('#referer\.php\?url=(.*)$#s',$result,$array2))

so print_r($array2) will output:

Array
(
    [0] => referer.php?url=http://www.example.com
    [1] => http://www.example.com
)

that is the result you want. Hope it helps!

if your input is: <td align="center" width="90%"><b><a target="_blank" href="/referer.php?url=http://www.example.com?somethin=1234">Go to this homepage</a></b>

and you want http://www.example.com?somethin=1234,

Your regex would look like this:

/referer\.php\?url=([^"]*)

That would make your php look like this:

if(preg_match('#/referer\.php\?url=([^"]*)#',$result,$array2)){ 
    print_r($array2);
}