How do I get a website's IP address using Python 3.x?

I have a s开发者_运维知识库tring representing a domain name. How can I get the corresponding IP address using Python 3.x? Something like this:

>>> get_ip('http://www.stackoverflow.com')
'64.34.119.12'

>>> import socket

>>> def get_ips_for_host(host):
        try:
            ips = socket.gethostbyname_ex(host)
        except socket.gaierror:
            ips=[]
        return ips

>>> ips = get_ips_for_host('www.google.com')
>>> print(repr(ips))
('www.l.google.com', [], ['74.125.77.104', '74.125.77.147', '74.125.77.99'])

Python 3.1.3 (r313:86834, Nov 27 2010, 18:30:53) [MSC v.1500 32 bit (Intel)] on win32
>>> import socket
>>> socket.gethostbyname('cool-rr.com')
'174.120.139.162'

Note that:

• gethostbyname() doesn't work with IPv6.
• gethostbyname() uses the C call gethostbanme(), which is deprecated.

If these are problematic, use socket.getaddrinfo() instead.

The easiest way is to use socket.gethostbyname(). This does not support IPv6, though, and is based on the deprecated C call gethostbanme(). If you care about these problems, you can use the more versatile socket.getaddrinfo() instead.

Here is full example, how you can get a website's IP address using Python

import urllib.parse
import socket
import dns.resolver

def get_ip(target):
    try:
        print(socket.gethostbyname(target))
    except socket.gaierror:
        res = head(target, allow_redirects=True)
        try:
            print(r.headers['Host'])
        except KeyError:
            parsed_url = urllib.parse.urlparse(target)
            hostname = parsed_url.hostname
            try:
                answers = dns.resolver.query(hostname, 'A')
                for rdata in answers:
                    print(rdata.address)
            except dns.resolver.NXDOMAIN:
                print('ip not found')

get_ip('example.com')