Regular expression for UTF-8 language

my application also supports punjabi(\u0A00-\u0A7F) i tried following code

Pattern classPattern = Pattern.compile("\u0A00-\u0A7F ");
    Matcher classMatcher = classPattern.matcher("ਭਾਸ਼ਾ ਸੰਦ");
            if (classMatcher.find()) {
              System.ou开发者_如何学Ct.println("yes");
            }else{
                System.out.println("no");
            }

i am getting "no" as output though i provided punjabi charactes in matcher()

any idea why??

Should that pattern be "[\u0A00-\u0A7F ]"? It looks to me like you're trying to match four characters in a specific order, but give the matcher six characters as input.

[\u0A00-\u0A7F ]*

Without the asterisk, you'll match only a single character. You can replace the * with +, then empty strings won't be accepted.

Take a look at the Pattern class JavaDocs. It's extremely useful to get a good and quick understanding of regexes.

because "asdsa " is not punjabi [the pattern you gave will look for pubjabi chars ,a dn abc aren't]