Extending several lists elegantly

Given several lists:

a = ["a1", "a2", "a3"]
b = ["b1", "b2", "b3"]
...
n = ["n1", "n2", "n3"]

And a list of new values:

new_vals = ["开发者_开发问答a4", "b4", "n4"]

I would like to get:

["a1", "a2", "a3", "a4"]
["b1", "b2", "b3", "b4"]
...
["n1", "n2", "n3", "n4"]

I can do this with loops and temporary variables, of course. It seems like come combination of zip, map, and list.extend should do it more elegantly, but is eluding me.

Something like this:

a = ["a1", "a2", "a3"]
b = ["b1", "b2", "b3"]

# Put the list a, b ... in a big_list. 
big_list = [a, b]

new_vals = ["a4", "b4", "n4"]

for i, new_val in enumerate(new_vals):
    big_list[i].append(new_val)

Suppose you have a list of lists:

lsts = [ ['a1','a2','a3'],
         ['b1','b2','b3'],
         ['c1','c2','c3'] ]

and a list that you of new values that you want to append to the end of each list in lsts:

lst = [ 'a4', 'b4', 'c4' ]

Then you can use a list comprehension:

new_lsts = [l + [x] for l, x in zip(lsts, lst)]

A map() oriented solution:

a = ["a1", "a2", "a3"]
b = ["b1", "b2", "b3"]
n = ["n1", "n2", "n3"]
new_vals = ["a4", "b4", "n4"]

map(lambda lst, x: lst.append(x), (a, b, n), new_vals)

And incorporating the list of lists suggestions above:

lsts = [['a1','a2','a3'],
        ['b1','b2','b3'],
        ['c1','c2','c3']]
new_vals = ["a4", "b4", "c4"]
map(lambda lst, x: lst.append(x), lsts, new_vals)

This might be preferable since it modifies lsts in-place instead of creating a new list of lists.