Retrieve gtalk nickname in python xmpp

In python xmpp module, I'm able to retrieve the nickname of any contacts as follows:

self.connection.auth(userJid.getNode(), self.password)
self.roster = self.connection.getRoster()  
name = self.roster.getName(buddyJid)

..where buddyJid is of the form user@gmail.com.

Now, I need to retrieve the nickname of the user who authentic开发者_高级运维ates the connection (userJid). I cannot find the name using the above method. Which method can I use retrieve the name of the current user?

This information is not in the roster. You will need to query the clients individually and get their vCard by sending this IQ :

<iq from='stpeter@jabber.org/roundabout'
    id='v1'
    type='get'>
  <vCard xmlns='vcard-temp'/>
</iq>

Thank you nicholas_o, this is a sample function I put together based your suggestion. (The XML logic isn't ideal, but it was sufficient for the simple task I needed this for)

def vcard(disp, jid):
    msg = xmpp.protocol.Iq()
    msg.setType('get')
    msg.setTo(jid)
    qc = msg.addChild('vCard')
    qc.setAttr('xmlns', 'vcard-temp')
    rep = disp.SendAndWaitForResponse(msg)
    # to see what other fields are available in the XML output:
    # print rep
    userid=fname=lname=title=department=region=None
    for i in rep.getChildren():
        for j in i.getChildren():
            if j.getName() == "TITLE":
                title = j.getData().encode('utf-8')
            for k in j.getChildren():
                if k.getName() == "GIVEN":
                    fname = k.getData().encode('utf-8')
                if k.getName() == "FAMILY":
                    lname = k.getData().encode('utf-8')
                if k.getName() == "ORGUNIT":
                    department = k.getData().encode('utf-8')
                if k.getName() == "REGION":
                    region = k.getData().encode('utf-8')
    return fname, lname, title, department, region