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How to open a file with the standard application?

My application prints a PDF to a temporary file. How can I open that file with the default application in Python?

I need a solution for

Related

  • Open document with default application in Python


os.startfile is only available for windows for now, but xdg-open will be available on any unix client running X.

if sys.platform == 'linux2':
    subprocess.call(["xdg-open", file])
else:
    os.startfile(file)


on windows it works with os.system('start <myFile>'). On Mac (I know you didn't ask...) it's os.system('open <myFile>')


Open file using an application that your browser thinks is an appropriate one:

import webbrowser
webbrowser.open_new_tab(filename)


if linux:
    os.system('xdg-open "$file"') #works for urls too
else:
    os.system('start "$file"') #a total guess


A small correction is necessary for NicDumZ's solution to work exactly as given. The problem is with the use of 'is' operator. A working solution is:

if sys.platform == 'linux2':
    subprocess.call(["xdg-open", file])
else:
    os.startfile(file)

A good discussion of this topic is at Is there a difference between `==` and `is` in Python?.


Ask your favorite Application Framework for how to do this in Linux.

This will work on Windos and Linux as long as you use GTK:

import gtk
gtk.show_uri(gtk.gdk.screen_get_default(), URI, 0)

where URI is the local URL to the file

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