mysql_real_escape_string() is not escaping anything

1. would I need to use real escape in both my INSERT and SELECT FROM statements开发者_JAVA技巧?

2. why the syntax I'm using in the following example isn't working (It's just one of the many ways I've tried)?

   //insert user input for word 1
   $sql = "INSERT INTO test (Word1, Word2, Word3, Word4, Word5)
   VALUES('$Word1','$Word2','$Word3','$Word4','$Word5')",
   mysql_real_escape_string($Word1),
   mysql_real_escape_string($Word2),
   mysql_real_escape_string($Word3),
   mysql_real_escape_string($Word4),
   mysql_real_escape_string($Word5);
   if(!mysql_query($sql,$con))
   {
     die('Error: ' . mysql_error());
   }
   

It looks like you are trying to use sprintf(), to do so properly you need to reformat your code a little:

$sql = sprintf("INSERT INTO test (Word1, Word2, Word3, Word4, Word5)
VALUES('%s','%s','%s','%s','%s')",
mysql_real_escape_string($Word1),
mysql_real_escape_string($Word2),
mysql_real_escape_string($Word3),
mysql_real_escape_string($Word4),
mysql_real_escape_string($Word5)
);

I highly recommend that you avoid escaping altogether, and move directly to prepared statements with mysqli::prepare, perhaps via PDO. It's ultimately simpler and safer:

$dsn = 'mysql:dbname=test;host=127.0.0.1';
$user = 'dbuser';
$password = 'dbpass';

$dbh = new PDO($dsn, $user, $password);

$sql =
    'INSERT INTO mytable ' .
    '(Word1, Word2, Word3, Word4, Word5)' .
    'VALUES(?, ?, ?, ?, ?)';

$stmt = $dbh->prepare($sql);

$words = array('word1', 'word2', 'word3', 'word4', 'word5');
$stmt->execute($words);

$words = array('word6', 'word7', 'word8', 'word9', 'word10');
$stmt->execute($words);