开发者

Sending an Email with python using the SMTP Library

import smtplib

def prompt(prompt):
    return raw_input(prompt).strip()

fromaddr = prompt("From: ")
toaddrs  = prompt("To: ").split()
print "Enter message, end with ^D (Unix) or ^Z (Windows):"


msg = ("From: %s\r开发者_StackOverflow\nTo: %s\r\n\r\n"
       % (fromaddr, ", ".join(toaddrs)))
while 1:
    try:
        line = raw_input()
    except EOFError:
        break
    if not line:
       break
    msg = msg + line

    print "Message length is " + repr(len(msg))

server = smtplib.SMTP('smtp.live.com:25')
server.set_debuglevel(1)
server.sendmail(fromaddr, toaddrs, msg)
server.quit()

I'm trying to send an Email using that example, but it doesnt work, I dont get any error it just doesn't send anything, I'm trying to send it to a hotmail email. Any help will be appreciated, Thanks.


Your call to smtplib.SMTP() uses invalid arguments. According to the smtplib docs:

SMTP([host[, port[, local_hostname[, timeout]]]])

So, the SMTP constructor takes the optional arguments for hostname, port etc. But you've passed port and hostname as one argument (server = smtplib.SMTP('smtp.live.com:25')).

Provided you have everything else right, if you change that line to read server = smtplib.SMTP('smtp.live.com', 25).

If your server requires authentication (and I suspect it does), before you actually send the email you'll want to call server.login(user, password) to login so you can actually send the message.

0

上一篇:

下一篇:

精彩评论

暂无评论...
验证码 换一张
取 消

最新问答

问答排行榜