PHP reading file

I am trying to read a formatted file

name (read this into variable)

10 10 (read into separate variables)

the rest into array

line

line

line

line

to clarify this is for an upload script which i already finished when a user uplo开发者_开发知识库ads a file formatted like that it reads it in the way described above

 $fname =  'test.txt';

 $lines = file("$fname", "r");

while($lines as $currenline){

I am trying to put the name, width, height into variables
    then the rest into the array

}

will this help

Not 100% sure what you're asking for but maybe this can get you started:

$fname =  'test.txt';

$lines = file("$fname", "r");

foreach($lines as $line) {
    $parts = explode(' ', $line);
    $name = $parts[0];
    $width = $parts[1];
    $height = $parts[2];

    // Do whatever you want with the line data here
}

It assumes all input lines are well formatted of course.

$fh = fopen( $fname, 'r' );

$name = fgets( $fh );
$dimensions = split( ' ', fgets($fh) );
$length = $dimensions[0];
$width = $dimensions[1];

$lines = array();

while ( $line = fgets( $fh ) $lines[] = $line;

I never tested this, but it should work if your files are constant. The while loop maybe off, and need some re-working if it doesn't work, keeping in mind that fgets returns false if an error occurs or is unable to read the file.

$lines already contains almost what you need, just pull out the relevant pieces.

$fname =  'test.txt';
$lines = file("$fname", "r");
$name = $lines[0];
list($height, $width) = explode(' ', $lines[1]);
$lines = array_slice($lines, 2);

Note this doesn't have any error checking, so you might want to add some.

As suggested in the comments you can also do this using array_shift:

$fname =  'test.txt';
$lines = file("$fname", "r");
$name = array_shift($lines);
list($height, $width) = explode(' ', array_shift($lines));
// $lines now contains only the rest of the lines in the file.