Is my programming logic correct here?
const char IsPressed = 1; // 1
const char WasHeldDown = 2; // 10
const char IsFirstPress = 4; // 100
char* keystates[256];
Class::CalculateKeyStates()
{
for(int i = 0; i < 256; ++i)
{
if(this->IsDown(i))
{
keystates[i] |= IsPressed; // turn on
if(keystates[i] & WasHeldDown)
{
//keystates[i] |= IsFirstPress;
keystates[i] &= ~IsFirstPress; // turn off
}
else
{
keystates[i] |= WasHeldDown + IsFirstPress; // Turn on
}
}
else
{
keystates[i] = 0; // Turn ALL off
}
}
}
This function would be a member function of a class, Class. The other member fun开发者_Python百科ction, IsDown, will return a true if the key in question is down and false if not.
Can you see any way of further improving this function?
Thanks
EDIT:
I will expand a bit as to what is done why. This is a modification of an bit of code that works through an array keyStates (which was a struct of three bools) setting IsPressed to false for all of the keys. then again setting Ispressed to the value of this->IsDown and then a third time looping through checking if the key had been held, if it has then its no longer the first press so set that to false. if it was not held down, then set first press to true and was held to true as well, so next time it is flagged as having been held.
EDIT2:
Added some comments to code and corrected one line
Personally, I would define the key-states as disjoint states and write a simple state-machine, thus:
enum keystate
{
inactive,
firstPress,
active
};
keystate keystates[256];
Class::CalculateKeyStates()
{
for (int i = 0; i < 256; ++i)
{
keystate &k = keystates[i];
switch (k)
{
inactive:
k = (isDown(i)) ? firstPress : inactive;
break;
firstPress:
k = (isDown(i)) ? active : inactive;
break;
active:
k = (isDown(i)) ? active : inactive;
break;
}
}
}
This is easier to extend, and easier to read if it gets any more complex.
You are always setting IsFirstPress
if the key is down, which might not be what you want.
I'm not sure what you want to achieve with IsFirstPress
, as the keystate cannot remember any previous presses anyways. If you want to mark with this bit, that it's the first time you recognized the key being down, then your logic is wrong in the corresponding if
statement.
keystates[i] & WasHeldDown
evaluates to true if you already set the bit WasHeldDown
earlier for this keystate.
In that case, what you may want to do is actually remove the IsFirstPress
bit by xor-ing it: keystates[i] ^= IsFirstPress
精彩评论