Python Class with integer emulation
Given is the following example:
class Foo(object):
def __init__(self, value=0):
self.value=value
def __int__(self):
return self.value
I want to have a class开发者_Go百科 Foo, which acts as an integer (or float). So I want to do the following things:
f=Foo(3)
print int(f)+5 # is working
print f+5 # TypeError: unsupported operand type(s) for +: 'Foo' and 'int'
The first statement print int(f)+5
is working, cause there are two integers. The second one is failing, because I have to implement __add__
to do this operation with my class.
So to implement the integer behaviour, I have to implement all the integer emulating methods. How could I get around this. I tried to inherit from int
, but this attempt was not successful.
Update
Inheriting from int
fails, if you want to use a __init__
:
class Foo(int):
def __init__(self, some_argument=None, value=0):
self.value=value
# do some stuff
def __int__(self):
return int(self.value)
If you then call:
f=Foo(some_argument=3)
you get:
TypeError: 'some_argument' is an invalid keyword argument for this function
Tested with Python 2.5 and 2.6
In Python 2.4+ inheriting from int works:
class MyInt(int):pass
f=MyInt(3)
assert f + 5 == 8
You need to override __new__
, not __init__
:
class Foo(int):
def __new__(cls, some_argument=None, value=0):
i = int.__new__(cls, value)
i._some_argument = some_argument
return i
def print_some_argument(self):
print self._some_argument
Now your class work as expected:
>>> f = Foo(some_argument="I am a customized int", value=10)
>>> f
10
>>> f + 8
18
>>> f * 0.25
2.5
>>> f.print_some_argument()
I am a customized int
More information about overriding new
can be found in Unifying types and classes in Python 2.2.
Try to use an up-to-date version of python. Your code works in 2.6.1.
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