subprocess() arguments in Python

I have an argument in Python that is screwing up my subprocess() command. The argument is:

--server-args="-screen 0, 1280x800x24"


args = [
  'xvfb-run',
  '--server-args="-screen 0, 1280x800x24"',
  '/usr/bin/python',
  '/root/AdamN-python-webkit2png-3ae4322/webkit2png.py',
  '-o',
  filename,
  url,
]

I think it's escaping the double quotes.开发者_StackOverflow Is there a work around for this?

While you've probably figured this out in the past two years, I had this same problem today. The solution:

import subprocess
subprocess.check_call(['xvfb-run', '-s', '-screen 0 1024x768x24', 
                       'CutyCapt', 
                       '--url=http://www.google.com/',
                       '--out=google.png'])

or

import subprocess
subprocess.check_call(['xvfb-run', '--server-args=-screen 0 1024x768x24', 
                       'CutyCapt', 
                       '--url=http://www.google.com/',
                       '--out=google4.png'])

Assuming you have xvfb installed. I am using CutyCapt as my sample application that requires an X framebuffer to run (its a program that converts webkit pages to images and requires an X server).

This is Python code, not a shell command line.

A shell command line eats the quotes to keep the spaces - in Python, the spaces are kept by a different means, so the quotes are passed on as-is and become part of the argument the called program actually sees.