How do I specify a range of unicode characters
How do I specify a range of unicode characters from ' '
(space) to \u00D7FF
?
I have a regular expression like r'[\u0020-\u00D7FF]'
and it won't compile saying that it's a bad range. I am new to Unicode regular expressions so I 开发者_如何学Gohaven't had this problem before.
Is there a way to make this compile or a regular expression that I'm forgetting or haven't learned yet?
The syntax of your unicode range will not do what you expect.
The raw
r''
string prevents\u
escapes from being parsed, and the regex engine will not do this. The only range in this set is[0-\]
:>>> re.compile(r'[\u0020-\u00d7ff]', re.DEBUG) in literal 117 literal 48 literal 48 literal 50 range (48, 117) literal 48 literal 48 literal 100 literal 55 literal 102 literal 102
Making it a Unicode literal causes
\u
parsing while leaving other backslashes alone (although that’s not a concern here), but the leading zeroes are messing it up. The syntax is\uxxxx
or\Uxxxxxxxx
, so it’s parsed as "\u00d7
,f
,f
".>>> re.compile(ur'[\u0020-\u00d7ff]', re.DEBUG) in range (32, 215) literal 102 literal 102
Removing the leading zeroes or switching to
\U0000d7ff
will fix it:>>> re.compile(ur'[\u0020-\ud7ff]', re.DEBUG) in range (32, 55295)
If you're using Python 2.x, you should make sure you're specifying a unicode string (with u'', or the "unicode" built-in):
>>> r = re.compile(u'[\u0020-\uD7FF]')
>>> r.search(u'foo \uD7F0 bar')
<_sre.SRE_Match object at 0xb7084950>
r.search(u' ')
<_sre.SRE_Match object at 0xb7084b48>
Using raw strings (as you are, with r'') gives you the (ascii) string composed by "backstroke" + the letter "u" plus the number 0 plus...
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