Shortest way to break-up long string (add whitespace) after 60 chars?
I'm processing a bunch of strings and displaying them on a web page.
Unfortunately if a string contains a word that is longer than 60 chars it makes my design implode.
Therefore i'm looking for the easiest, most efficient way to add a whitespace after every 60 chars without wh开发者_如何学编程itespaces in a string in python.
I only came up with clunky solutions like using str.find(" ")
two times and check if the index difference is > 60
.
Any ideas appreciated, thanks.
>>> import textwrap >>> help(textwrap.wrap) wrap(text, width=70, **kwargs) Wrap a single paragraph of text, returning a list of wrapped lines. Reformat the single paragraph in 'text' so it fits in lines of no more than 'width' columns, and return a list of wrapped lines. By default, tabs in 'text' are expanded with string.expandtabs(), and all other whitespace characters (including newline) are converted to space. See TextWrapper class for available keyword args to customize wrapping behaviour. >>> s = "a" * 20 >>> s = "\n".join(textwrap.wrap(s, width=10)) >>> print s aaaaaaaaaa aaaaaaaaaa
Any extra newlines inserted will be treated as space when the web page is processed by the browser.
Alternatively:
def break_long_words(s, width, fix):
return " ".join(x if len(x) < width else fix(x) for x in s.split())
def handle_long_word(s): # choose a name that describes what action you want
# do something
return s
s = "a" * 20
s = break_long_words(s, 60, handle_long_word)
def make_wrappable(your_string):
new_parts = []
for x in your_string.split():
if len(x)>60:
# do whatever you like to shorten it,
# then append it to new_parts
else:
new_parts.append(x)
return ' '.join(new_parts)
def splitLongWord ( word ):
segments = list()
while len( word ) > 0:
segments.append( a[:60] )
word = a[60:]
return ' '.join( segments )
myString = '...' # a long string with words that are longer than 60 characters
words = list()
for word in myString.split( ' ' ):
if len( word ) <= 60:
words.append( word )
else:
words.extend( splitLongWord( word ) )
myString = ' '.join( words )
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