Passing blocks into nested method within class_eval in Ruby?
I want to be able to define a block, and later evaluate that block from within a dynamically generated module/class. It seems like I could accomplish this somehow using eval
and block.binding
, but I haven't figured it out.
I have this as the base:
def define_module(name, &block)
name = name.to_s.gsub(/\/(.?)/) { "::#{$1.upcase}" }.gsub(/(?:^|_)(.)/) { $1.upcase }
parts = name.split("::")
parts.each_with_index do |part, index|
sub_name = parts[0..index].join("::")
eval("module #{sub_name}; end")
end
clazz = eval(name)
clazz.class_eval(&block) if block_given?
clazz
end
def add_module(name, &block)
module_block = block
define_module(name).class_eval <<-EOF
def self.included(base)
base.class_eval do
# something like this, I'm stuck
instance_eval(&#{module_block})
end
end
E开发者_StackOverflow社区OF
end
And I want to use it like this:
add_module("My::Library") do
def a_method
"added 'a_method'"
end
end
class ::User
include My::Library
end
user = ::User.new
assert_equal "added 'a_method'", user.a_method
Is there any way to do something like that?
This works:
def add_module(name, &block)
define_module(name).class_eval do
class << self; self; end.send(:define_method, :included) { |base|
base.class_eval(&block)
}
end
end
add_module("My::Library") do
def a_method
"added 'a_method'"
end
end
class ::User
include My::Library
end
user = ::User.new
user.a_method #=> "added a_method"
EDIT:
Why don't you just do this instead? Much simpler, and it's actually the job of a module:
def add_module(name, &block)
define_module(name).class_eval(&block)
end
精彩评论