in python how do I convert a single digit number into a double digits string?
So say i have
a = 5
i want to prin开发者_C百科t it as a string '05'
In python 3.6, the fstring or "formatted string literal" mechanism was introduced.
f"{a:02}"
is the equivalent of the .format format below, but a little bit more terse.
python 3 before 3.6 prefers a somewhat more verbose formatting system:
"{0:0=2d}".format(a)
You can take shortcuts here, the above is probably the most verbose variant. The full documentation is available here: http://docs.python.org/3/library/string.html#string-formatting
print "%02d"%a
is the python 2 variant
The relevant doc link for python2 is: http://docs.python.org/2/library/string.html#format-specification-mini-language
a = 5
print '%02d' % a
# output: 05
The '%' operator is called string formatting operator when used with a string on the left side. '%d'
is the formatting code to print out an integer number (you will get a type error if the value isn't numeric). With '%2d
you can specify the length, and '%02d'
can be used to set the padding character to a 0 instead of the default space.
>>> print '{0}'.format('5'.zfill(2))
05
Read more here.
>>> a=["%02d" % x for x in range(24)]
>>> a
['00', '01', '02', '03', '04', '05', '06', '07', '08', '09', '10', '11', '12', '13', '14', '15', '16', '17', '18', '19', '20', '21', '22', '23']
>>>
It is that simple
In Python 3.6 you can use so called f-strings. In my opinion this method is much clearer to read.
>>> f'{a:02d}'
'05'
In Python3, you can:
print("%02d" % a)
Based on what @user225312 said, you can use .zfill() to add paddng to numbers converted to strings.
My approach is to leave number as a number until the moment you want to convert it into string:
>>> num = 11
>>> padding = 3
>>> print(str(num).zfill(padding))
011
Branching off of Mohommad's answer:
str_years = [x for x in range(24)]
#[0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23]
#Or, if you're starting with ints:
int_years = [int(x) for x in str_years]
#Formatted here
form_years = ["%02d" % x for x in int_years]
print(form_years)
#['00', '01', '02', '03', '04', '05', '06', '07', '08', '09', '10', '11', '12', '13', '14', '15', '16', '17', '18', '19', '20', '21', '22', '23']
df["col_name"].str.rjust(4,'0')#(length of string,'value') --> ValueXXX --> 0XXX
df["col_name"].str.ljust(4,'0')#(length of string,'value') --> XXXValue --> XXX0
If you are an analyst and not a full stack guy, this might be more intuitive:
[(str('00000') + str(i))[-5:] for i in arange(100)]
breaking that down, you:
start by creating a list that repeats 0's or X's, in this case, 100 long, i.e., arange(100)
add the numbers you want to the string, in this case, numbers 0-99, i.e., 'i'
keep only the right hand 5 digits, i.e., '[-5:]' for subsetting
output is numbered list, all with 5 digits
This is a dumb solution but I was getting type errors with the other solutions above. So if all else fails, yolo:
images3digit = []
for i in images:
if len(i)==1:
i = '00'+i
images3digit.append(i)
elif len(i)==2:
i = '0'+i
images3digit.append(i)
elif len(i)==3:
images3digit.append(i)
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