Python list function argument names [duplicate]
Is there a way to get the parameter names a function takes?
def foo(bar, buz):
pass
magical_way(foo) == ["bar", "buz"]
Use the inspect module from Python's standard library (the cleanest, most solid way to perform introspection).
Specifically, inspect.getargspec(f)
returns the names and default values of f
's arguments -- if you only want the names and don't care about special forms *a
, **k
,
import inspect
def magical_way(f):
return inspect.getargspec(f)[0]
completely meets your expressed requirements.
>>> import inspect
>>> def foo(bar, buz):
... pass
...
>>> inspect.getargspec(foo)
ArgSpec(args=['bar', 'buz'], varargs=None, keywords=None, defaults=None)
>>> def magical_way(func):
... return inspect.getargspec(func).args
...
>>> magical_way(foo)
['bar', 'buz']
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