Calling lua functions from .lua's using handles?

I'm working on a small project trying to integrate lua with c++. My problem however is as follows:

I have multiple lua scripts, lets call them s1.lua s2.lua and s3.lua. Each of these has the following functions: setVars() and executeResults().

Now I am able to to call a lua file through LuaL_dofile and immediately after use setVars() and/or executeResults(). The problem here however is that after I load s2.lua I can no longer call the functions of s1.lua. This would mean I have to r开发者_开发知识库edo the LuaL_dofile on s1.lua to regain access to the function and by doing so I lose access to the functions in s2.lua.

Is there a way to simply load all lua files in a row, and afterwards start calling their functions at will? Something like s1->executeResults() s5->executeResults() s3->setVars() etc.

I currently already have a system in place using boost::filesystem to detect all lua files in a folder, I then save these files names in a vector and then simply iterate over the vector to load each lua file in a row.

Foregoing the filling of the vector with lua file names my plugin load function looks like this at the moment:

void Lua_plugin::load_Plugins(){
 std::vector<std::string>::const_iterator it;
 for (it=Lua_PluginList.begin(); it!=Lua_PluginList.end(); it++){
  std::cout<<"File loading: " << *it << std::endl;
  std::string filename =  *it;
  std::string filepath = scriptdir+filename;
  if (luaL_loadfile(L, filepath.c_str()) || lua_pcall(L, 0, 0, 0)) {
   std::cout << "ScriptEngine: error loading script. Error returned was: " << lua_tostring(L, -1) << std::endl;
  }
 }
}

To make it a bit more clear, all I have in the .lua's is something like this:

-- s1.lua

setVars()
--do stuff
end

executeResults()
--dostuff
end

etc, but I would like to be able to call s1.lua's setVars() and s2.lua's setVars() after simply having loaded both in a row.

This is effectively what gwell proposed using the C API:

#include <stdio.h>

#include "lua.h"

static void
executescript(lua_State *L, const char *filename, const char *function)
{
    /* retrieve the environment from the resgistry */
    lua_getfield(L, LUA_REGISTRYINDEX, filename);

    /* get the desired function from the environment */
    lua_getfield(L, -1, function);

    return lua_call(L, 0, 0);
}

static void
loadscript(lua_State *L, const char *filename)
{
    /* load the lua script into memory */
    luaL_loadfile(L, filename);

    /* create a new function environment and store it in the registry */
    lua_createtable(L, 0, 1);
    lua_getglobal(L, "print");
    lua_setfield(L, -2, "print");
    lua_pushvalue(L, -1);
    lua_setfield(L, LUA_REGISTRYINDEX, filename);

    /* set the environment for the loaded script and execute it */
    lua_setfenv(L, -2);
    lua_call(L, 0, 0);

    /* run the script initialization function */
    executescript(L, filename, "init");
}

int
main(int argc, char *argv[])
{
    lua_State *L;
    int env1, env2;

    L = (lua_State *) luaL_newstate();
    luaL_openlibs(L);

    loadscript(L, "test1.lua");
    loadscript(L, "test2.lua");

    executescript(L, "test1.lua", "run");
    executescript(L, "test2.lua", "run");
    executescript(L, "test2.lua", "run");
    executescript(L, "test1.lua", "run");

    return 0;
}

Test scripts:

-- test1.lua
function init() output = 'test1' end
function run() print(output) end

-- test2.lua
function init() output = 'test2' end
function run() print(output) end

Output:

test1
test2
test2
test1

I omitted all error handling for brevity, but you'll want to check the return value of luaL_loadfile and use lua_pcall instead of lua_call.

The setfenv() function can be used to create a sandbox or environment for each file loaded.

This example shows that all three files could be loaded with conflicting functions and that the functions can be called in any order. Similar code could be written in C++. This example only exports the print function to each environment, more might be needed in your scenario.

function newEnv()
  -- creates a simple environment
  return {["print"]=print}
end

local e={} -- environment table
local c    -- chunk variable

-- first instance
c = loadstring([[function f() print("1") end]])
e[#e+1] = newEnv()
setfenv(c, e[#e]) -- set the loaded chunk's environment
pcall(c) -- process the chunk (places the function into the enviroment)

-- second instance
c = loadstring([[function f() print("2") end]])
e[#e+1] = newEnv()
setfenv(c, e[#e])
pcall(c)

-- third instance
c = loadstring([[function f() print("3") end]])
e[#e+1] = newEnv()
setfenv(c, e[#e])
pcall(c)

pcall(e[3].f) --> 3
pcall(e[2].f) --> 2
pcall(e[1].f) --> 1
pcall(e[1].f) --> 1
pcall(e[2].f) --> 2
pcall(e[3].f) --> 3

You could create a new state lua_newstate() for each file. This would be easier than my previous answer. However, it may have a performance penalty.