Python RegEx skipping the first few characters?
Hey I have a fairly basic q开发者_如何学Gouestion about regular expressions. I want to just return the text inside (and including) the body tags, and I know the following isn't right because it'll also match all the characters before the opening body tag. I was wondering how you would go about skipping those?
x = re.match('(.*<body).*?(</body>)', fileString)
Thanks!
I don't know Python, but here's a quick example thrown together using Beautiful Soup, which I often see recommended for Python HTML parsing.
import BeautifulSoup
soup = BeautifulSoup(fileString)
bodyTag = soup.html.body.string
That will (in theory) deal with all the complexities of HTML, which is very difficult with pure regex-based answers, because it's not what regex was designed for.
Here is some example code which uses regex to find all the text between <body>...</body> tags. Although this demonstrates some features of python's re module, note that the Beautiful Soup module is very easy to use and is a better tool to use if you plan on parsing HTML or XML. (See below for an example of how you could parse this using BeautifulSoup.)
#!/usr/bin/env python
import re
# Here we have a string with a multiline <body>...</body>
fileString='''baz<body>foo
baby foo
baby foo
baby foo
</body><body>bar</body>'''
# re.DOTALL tells re that '.' should match any character, including newlines.
x = re.search('(<body>.*?</body>)', fileString, re.DOTALL)
for match in x.groups():
print(match)
# <body>foo
# baby foo
# baby foo
# baby foo
# </body>
If you wish to collect all matches, you could use re.findall:
print(re.findall('(<body>.*?</body>)', fileString, re.DOTALL))
# ['<body>foo\nbaby foo\nbaby foo\nbaby foo\n</body>', '<body>bar</body>']
and if you plan to use this pattern more than once, you can pre-compile it:
pat=re.compile('(<body>.*?</body>)', re.DOTALL)
print(pat.findall(fileString))
# ['<body>foo\nbaby foo\nbaby foo\nbaby foo\n</body>', '<body>bar</body>']
And here is how you could do it with BeautifulSoup:
#!/usr/bin/env python
from BeautifulSoup import BeautifulSoup
fileString='''baz<body>foo
baby foo
baby foo
baby foo
</body><body>bar</body>'''
soup = BeautifulSoup(fileString)
print(soup.body)
# <body>foo
# baby foo
# baby foo
# baby foo
# </body>
print(soup.findAll('body'))
# [<body>foo
# baby foo
# baby foo
# baby foo
# </body>, <body>bar</body>]
You cannot parse HTML with regex. HTML is not a regular language. Use an HTML parser like lxml instead.
x = re.match('.*(<body>.*?</body>)', fileString)
Consider minidom for HTML parsing.
x = re.search('(<body>.*</body>)', fileString)
x.group(1)
Less typing than the match answers
Does your fileString contain multiple lines? In that case you may need to specify it or skip the lines explicitly:
x = re.match(r"(?:.|\n)*(<body>(?:.|\n)*</body>)", fileString)
or, more simply with the re module:
x = re.match(r".*(<body>.*</body>)", fileString, re.DOTALL)
x.groups()[0] should contain your string if x is not None.
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